How Many Total Atoms Are In 0.590 G Of P2o5
David Jones
Published May 11, 2026
How Many Total Atoms Are In 0.590 G Of P2o5
How many atoms are there in 0.760 g of P2O5? 3
Please help with the chemistry!
The first P2O5 calculation. = Grams / sesame
P2O5 = 2 x P (2 x 31.0) + 5 x O (5 x 16.0) = molar for 142 g / mol.
0.760 g P2O5 x (1 mol P2O5 / 142 g P2O5) = 0.00535 P2O5
0.00535 P2O5 x (6.02 x 10 23 molecules of P2O5 / 1 mole of P2O5) = 3.22 x 10 21 molecules of P2O5
Each P2O5 molecule has 2 P atoms and 5 O atoms (total = 7 atoms).
3.22 x 10 21 molecules of P2O5 x (7 atoms / 1 molecule of P2O5) = 2.25 x 10 22 atoms
You should make the following three changes: 1. From grams: M molar P2O5 is: 2 (30.97 g / mol) 5 (16.00 g / mol) = 141.94 g / mol. 2. Molecules: The number of evagadro is 6,022 × 1023 molecules / mol.
Jack, you take the last step: molecules turn into atoms.
